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Priscila0473
@Priscila0473
January 2020
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De as massa das moléculas:
HCl
H2S
Al2(SO4)
K3BO3
Be3[Fe(CN)6]2
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marianaab27
HCl = 35,5 + 1 = 36,5
H2S = 2(1)+32= 34
Al2(SO4) = 2(27)+32+4(16)= 150
K3BO3= 3(39)+11+3(16)= 176
Be3[Fe(CN)6]2 = 3(9)+2[56+6(12+14)]= 27+2[56+156]= 27+424=451
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Lista de comentários
H2S = 2(1)+32= 34
Al2(SO4) = 2(27)+32+4(16)= 150
K3BO3= 3(39)+11+3(16)= 176
Be3[Fe(CN)6]2 = 3(9)+2[56+6(12+14)]= 27+2[56+156]= 27+424=451