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IzzyAoki
@IzzyAoki
December 2019
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Demonstre, usando as fórmulas da adição, que :
a) sen (π - x) = sen x;
b) sen (2π - x) = -sen x.
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hcsmalves
A) sen(π - x) = senπcosx + senx cosπ = 0.cosx + senx . (-1 ) = 0 - senx = - senx
b) sen(2π - x) = sen2π cosx - senx cos2π = 0.cosx - senx . 1 = - senx
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IzzyAoki
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b) sen(2π - x) = sen2π cosx - senx cos2π = 0.cosx - senx . 1 = - senx