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Brunooohhh
@Brunooohhh
January 2020
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Derivada da função f(x)=
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Oguchi
F(x)=x^(3/2)
Como (x^n)'=n.x^(n-1):
f'(x)=3/2.x^(3/2-1)
f'(x)=3/2.x^(1/2)
f'(x)=(3√x)/2
1 votes
Thanks 1
Brunooohhh
tem certeza?
Oguchi
Você mudou a função...
Oguchi
Vou arrumar a resposta
Brunooohhh
mudei não, era a mesma coisa. x ^3/2
Oguchi
Pensei que fosse (x^3)/2
Oguchi
Taí, de qualquer jeito
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Como (x^n)'=n.x^(n-1):
f'(x)=3/2.x^(3/2-1)
f'(x)=3/2.x^(1/2)
f'(x)=(3√x)/2