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Lorenamor
@Lorenamor
September 2019
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Desenvolva o binomio
(y-√x) ³
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marcilio69abreu
[y - Vx]³ =
[y - Vx][y - Vx]² =
[y - Vx][y² - 2yVx + x] =
y³ - 2y²Vx + yx - y²Vx + 2yx - xVx =
y³ - 3y²Vx + 3xy - xVx
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[y - Vx][y - Vx]² =
[y - Vx][y² - 2yVx + x] =
y³ - 2y²Vx + yx - y²Vx + 2yx - xVx =
y³ - 3y²Vx + 3xy - xVx