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Daninovelini
@Daninovelini
January 2020
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Determinar as coordenadas do vértice V da parábola que representa a função f(x)= x²-3x + 2
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Nooel
Temos a função: F(x)=x²-3x+2
Xv=-b/2a
Xv=-(-3)/2.1
Xv=3/2
Yv=-Δ/4a
Yv=-(-3²-4.1.2)/4
Yv=-1/4
C(3/2,-1/4)
Espero ter ajudado!
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Xv=-b/2a
Xv=-(-3)/2.1
Xv=3/2
Yv=-Δ/4a
Yv=-(-3²-4.1.2)/4
Yv=-1/4
C(3/2,-1/4)
Espero ter ajudado!