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12003
@12003
December 2019
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Determine a área de um triângulo equilátero cuja altura mede 6m.
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6^2 + (L/2)^2 = L^2
36 = 3L^2/4
144/3 = L^2
48 = L^2
L =4 raiz de 3
6*4 raiz de 3/ 2 = 24 raiz de 3/2 = 12 raiz de 3
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Lista de comentários
36 = 3L^2/4
144/3 = L^2
48 = L^2
L =4 raiz de 3
6*4 raiz de 3/ 2 = 24 raiz de 3/2 = 12 raiz de 3