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Oohmontana
@Oohmontana
January 2020
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Determine as medidas x e y indicadas no triângulo retângulo abaixo.
(Dados sen 35° = 0,574 cos 35° = 0,819)
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Tayanneq
Verified answer
CO - cateto oposto
CA- cateto adjacente
H- hipotenusa
sen 35° = CO/ H
0.574 = x / 6
x =3,444
cos 35° = CA / H
0.819 = y/6
y=4,914
71 votes
Thanks 137
oohmontana
OBRIGADAA A A A <3
matematicamtm
Resolução:
sen 35 = x/6
0,574 = x/6
x = 3,444 cm
cos 35 = y/6
0,819 = y/6
y = 4,914 cm
19 votes
Thanks 35
oohmontana
OBRIGADAA A A A A<3
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Lista de comentários
Verified answer
CO - cateto opostoCA- cateto adjacente
H- hipotenusa
sen 35° = CO/ H
0.574 = x / 6
x =3,444
cos 35° = CA / H
0.819 = y/6
y=4,914
sen 35 = x/6
0,574 = x/6
x = 3,444 cm
cos 35 = y/6
0,819 = y/6
y = 4,914 cm