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Juniorcesar
@Juniorcesar
April 2020
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Determine as raizes e as coordenadas da vertice da funçao de 2º grau : y= x² - 2x - 3
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3478elc
Verified answer
x² - 2x - 3 = 0
delta= (-2)^2 - 4.1.(-3)= 4 + 12= 16
x= 2 +/-V16 = 2+/- 4 ==> x1= 2+4 ==>
x1= 3
; x2 = 2 - 4 ==>
x2 = -1
2.1 2 2 2
Vertices
Xv= - b ==>Xv= -(-2) ==>
Xv= 1
2a 2.1
Yv= - delta ==> Yv= - 16 ==>
Yv= - 4
4a 4.1
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Verified answer
x² - 2x - 3 = 0delta= (-2)^2 - 4.1.(-3)= 4 + 12= 16
x= 2 +/-V16 = 2+/- 4 ==> x1= 2+4 ==>x1= 3 ; x2 = 2 - 4 ==> x2 = -1
2.1 2 2 2
Vertices
Xv= - b ==>Xv= -(-2) ==> Xv= 1
2a 2.1
Yv= - delta ==> Yv= - 16 ==> Yv= - 4
4a 4.1