Determine med DH.segue anexo.... Pergunta de ideia deDanielvr

Danielvr @Danielvr

December 2019 1 111 Report

Determine med DH.

segue anexo

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Thihefi Com pitagoras, calculamos AC
4²=2²+ AC²
16-4=AC²
AC= $\sqrt{12} =2 \sqrt{3}$

Agora calculamos AD
$(2 \sqrt{3} ) ^{2} = 2 ^{2} +AD ^{2}$
12-4=AD²
AD= $\sqrt{8} = 2 \sqrt{2}$

AD.DC=AC.DH
$2\sqrt{2} . 2 = 2 \sqrt{3} . DH$
$\frac{4 \sqrt{2} }{2 \sqrt{3} } =AD$
$\frac{2 \sqrt{2} }{ \sqrt{3} }$
$\frac{2 \sqrt{(2.3)} }{3}$
$\frac{2 \sqrt{6} }{3}$

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