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Sandra241
@Sandra241
January 2020
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Determine o valor de seno, cosseno e tangente de α no triângulo PQR.
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mozarth11
A² = 12² + 5²
a² = 144+25
a² = 169
a = \/169
a = 13
sen alfa = 12/13
cos alfa = 5/13
tg alfa = sen/cos = (12/13) / (5/13) = 12/13 * 13/5 = 12/5
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a² = 144+25
a² = 169
a = \/169
a = 13
sen alfa = 12/13
cos alfa = 5/13
tg alfa = sen/cos = (12/13) / (5/13) = 12/13 * 13/5 = 12/5