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JerffersonMostra
@JerffersonMostra
January 2020
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Determine quantas raízes naturais tem a equação 3
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3x + 5 - 2x² = 0
- 2x² + 3x + 5 = 0
Δ = 9 + 40
Δ = 49
x = -3 +-√49/-4
x = -3 +-7/-4
x' =-3+7/-4
x' = 4/-4
x' = -1 (é inteiro e não natural)
x'' = -3-7/-4
x'' = -10/-4
x'' = 2,5 (é racional e não natural)
Nenhuma raiz natural
ok
1 votes
Thanks 2
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3x + 5 - 2x² = 0
- 2x² + 3x + 5 = 0
Δ = 9 + 40
Δ = 49
x = -3 +-√49/-4
x = -3 +-7/-4
x' =-3+7/-4
x' = 4/-4
x' = -1 (é inteiro e não natural)
x'' = -3-7/-4
x'' = -10/-4
x'' = 2,5 (é racional e não natural)
Nenhuma raiz natural ok