Determine x e y nas seguintes igualdades:
a) 4 + 2yi = (x+3)+ (x-y)i
b) (1-x) + (3+y)i = 4+6i
a) 4 + 2yi = (x+3)+ (x-y)i
b) (1-x) + (3+y)i = 4+6i
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a) 4 + 2yi = (x+3)+ (x-y)i
x + 3 = 4 ==> x = 4-3 ==> x = 1
x-y = 2y ==> 1 - y = 2y ==> 2y+y =1 ==> 3y=1 ==> y = 1/3
b) (1-x) + (3+y)i = 4+6i
1 - x = 4 ==> x = 1+4 ==> x = 5
3 + y = 6 ==> y = 6-3 ==> y = 3