Dados:
Q1 → 3×10⁻⁶C
Q2 → 5×10⁻⁶C
K₀ → 9×10⁹ n·m²/c²
d → 5cm → 5/100 = 0,05m
_________________
F= K₀·Q1·Q2/d²
F=9×10⁹·3×10⁻⁶·5×10⁻⁶/0,05²
F=9×10⁹·3×10⁻⁶·5×10⁻⁶/0,0025
F=9×10⁹·15·10⁻¹²/2,5×10⁻³
F=9×10⁹·6·10⁻⁹
F=54·10⁹⁺⁽⁻⁹⁾
F=54·10⁹⁻⁹
F=54·10⁰
F=54N
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Verified answer
Sabemos que:F = K*|Q|*|q| / d²
Então, temos que:
K = 9.10^9 N.m² / C
d = 5 cm = 5.10^-2 m
Q1 = 3.10^-6 C
Q2 = 5.10^-6 C
F = 9.10^9*|3.10^-6|*|5.10^-6| / (5.10^-2)²
F = 135.10^-3 / 25.10^-4
F = 5,4.10^-3*10^4
F = 5,4.10^1
F = 54 N
Boa tarde!
Dados:
Q1 → 3×10⁻⁶C
Q2 → 5×10⁻⁶C
K₀ → 9×10⁹ n·m²/c²
d → 5cm → 5/100 = 0,05m
_________________
F= K₀·Q1·Q2/d²
F=9×10⁹·3×10⁻⁶·5×10⁻⁶/0,05²
F=9×10⁹·3×10⁻⁶·5×10⁻⁶/0,0025
F=9×10⁹·15·10⁻¹²/2,5×10⁻³
F=9×10⁹·6·10⁻⁹
F=54·10⁹⁺⁽⁻⁹⁾
F=54·10⁹⁻⁹
F=54·10⁰
F=54N
_________________
Att;Guilherme Lima