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Paulog1986
@Paulog1986
December 2019
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Encontrar o termo geral da pg (5,15,45 A fórmula é an.qn-1
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PauloLuis
An = a1 . q^n-1
q = a2/a1
q = 15/5
q = 3
an = 5 . 3^n-1
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q = a2/a1
q = 15/5
q = 3
an = 5 . 3^n-1