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LadyOfGlasses
@LadyOfGlasses
December 2019
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Encontre a equação fundamental da reta que passa pelos pontos:
a) A (0,2) e B (2,3)
b) A (-1,2) e B (-2,5)
c) A (0,-3) e B (3,-2)
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A) 2=b
3=2a+b --> 3=2a+2
a= 1/2
f(x)= x/2+2
b)2=-a+b-- > b= 2+a
5=-2a+b--> 5=-2a+2+a
a=-3
b= -1
f(x)= -3x-1
c)-3=b
-2=3a+b --> -2=3a-3
a= 1/3
f(x)= x/3-3
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Lista de comentários
3=2a+b --> 3=2a+2
a= 1/2
f(x)= x/2+2
b)2=-a+b-- > b= 2+a
5=-2a+b--> 5=-2a+2+a
a=-3
b= -1
f(x)= -3x-1
c)-3=b
-2=3a+b --> -2=3a-3
a= 1/3
f(x)= x/3-3