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Yris30
@Yris30
December 2019
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Encontre os elementos da matriz:
A= (aij) 3×2 em que aij = 3i - j
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HelenaBC9
A11= 3 - 1 = 2
a12= 3-2=1
a21=6-1=5
a22=6-4=4
a31=9-1=8
a32=9-2=7
2 1
5 4
8 7
0 votes
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a12= 3-2=1
a21=6-1=5
a22=6-4=4
a31=9-1=8
a32=9-2=7
2 1
5 4
8 7