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Lucasalexand
@Lucasalexand
April 2020
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Equação do 2 grau
x²-5x+6=0
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Arianne86
Primeiro identificamos os coeficientes
x²-5x+6=0
a = 1
b = -5
c = 6
Aplicamos delta
∆ = b² - 4ac
∆ = (-5)² - 4.1.6
∆ = 25 - 24
∆ = 1
Agora aplicamos na formula
x = (-b +- √∆)/2a
x = [-(-5) +- √1]/ 2.1
x = (5 +- 1) /2
x' = (5+1)/2 ==> 6/2 ==> 3
x'' = (5-1)/2 ==> 4/2 ==> 2
Raízes são 2 e 3
1 votes
Thanks 3
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Lista de comentários
x²-5x+6=0
a = 1
b = -5
c = 6
Aplicamos delta
∆ = b² - 4ac
∆ = (-5)² - 4.1.6
∆ = 25 - 24
∆ = 1
Agora aplicamos na formula
x = (-b +- √∆)/2a
x = [-(-5) +- √1]/ 2.1
x = (5 +- 1) /2
x' = (5+1)/2 ==> 6/2 ==> 3
x'' = (5-1)/2 ==> 4/2 ==> 2
Raízes são 2 e 3