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Victoryasuellen
@Victoryasuellen
May 2020
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Equações de segundo grau
Determine as soluções das seguintes equações:
g) x²-3x-4=0
h) 5x²+4x-1=0
k)9x²-6x+1=0
q)x²-12x+36=0
v) 2x²=5x-8
w) x²-x=x-1
z) 7x²+3x+1 =3x²
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albertor
G) ^=(-3)²-4*1*(-4)
^=9+16
^=25
X=3+-RAIZde 25 / 2*1
x¹= 8 / 2 = 4
x²= -2 / 2 = -1
1 votes
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williammendes11
G)
x²-3x-4=0
Δ = b² - 4ac
Δ = (-3)² - 4(1)(-4)
Δ = 9 + 16
Δ = 25
x = -b +- √Δ /2a
x = 3 +- 5 /2
x1 = 8/2 = 4
x2 = -2/2 = -1
h) 5x²+4x-1=0
Δ = (4)² - 4(5)(-1)
Δ = 16 + 20
Δ = 36
x = -4 +- 6 /10
x1 = 2/10 = 1/5
x2 = -10/10 = -1
k)9x²-6x+1=0
Δ = (-6)² - 4(9)(1)
Δ = 36 - 36
Δ = 0
x = 6 +- 0 /18
x1 = x2 = 6/18 = 1/3
q)x²-12x+36=0
Δ = (-12)² - 4(1)(36)
Δ = 144 - 144
Δ = 0
x = 12 +- 0 /2
x1 = x2 = 12/2 = 6
v) 2x²=5x-8
2x²-5x+8=0
Δ = (-5)² - 4(2)(8)
Δ = 25 - 64
Δ = -39
x = 5 +- i√39 /4
x1 = 5/4 + i√39/4 = 1/4 (5 + i√39)
x2 = 5/4 - i√39/4 = 1/4 (5 - i√39)
w) x²-x=x-1
x²-x-x+1=0
x²-2x+1=0
Δ = (-2)² - 4(1)(1)
Δ = 4 - 4
Δ = 0
x = 2 +- 0 /2
x1 = x2 = 2/2 = 1
z) 7x²+3x+1 =3x²
7x²-3x²+3x+1=0
4x²+3x+1=0
Δ = (3)² - 4(4)(1)
Δ = 9 - 16
Δ = -7
x = -3 +- i√7 /8
x1 = -3/8 + i√7/8 = 1/8 (-3 + i√7)
x2 = -3/8 - i√7/8 = 1/8 (-3 - i√7)
1 votes
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^=9+16
^=25
X=3+-RAIZde 25 / 2*1
x¹= 8 / 2 = 4
x²= -2 / 2 = -1
Δ = b² - 4ac
Δ = (-3)² - 4(1)(-4)
Δ = 9 + 16
Δ = 25
x = -b +- √Δ /2a
x = 3 +- 5 /2
x1 = 8/2 = 4
x2 = -2/2 = -1
h) 5x²+4x-1=0
Δ = (4)² - 4(5)(-1)
Δ = 16 + 20
Δ = 36
x = -4 +- 6 /10
x1 = 2/10 = 1/5
x2 = -10/10 = -1
k)9x²-6x+1=0
Δ = (-6)² - 4(9)(1)
Δ = 36 - 36
Δ = 0
x = 6 +- 0 /18
x1 = x2 = 6/18 = 1/3
q)x²-12x+36=0
Δ = (-12)² - 4(1)(36)
Δ = 144 - 144
Δ = 0
x = 12 +- 0 /2
x1 = x2 = 12/2 = 6
v) 2x²=5x-8
2x²-5x+8=0
Δ = (-5)² - 4(2)(8)
Δ = 25 - 64
Δ = -39
x = 5 +- i√39 /4
x1 = 5/4 + i√39/4 = 1/4 (5 + i√39)
x2 = 5/4 - i√39/4 = 1/4 (5 - i√39)
w) x²-x=x-1
x²-x-x+1=0
x²-2x+1=0
Δ = (-2)² - 4(1)(1)
Δ = 4 - 4
Δ = 0
x = 2 +- 0 /2
x1 = x2 = 2/2 = 1
z) 7x²+3x+1 =3x²
7x²-3x²+3x+1=0
4x²+3x+1=0
Δ = (3)² - 4(4)(1)
Δ = 9 - 16
Δ = -7
x = -3 +- i√7 /8
x1 = -3/8 + i√7/8 = 1/8 (-3 + i√7)
x2 = -3/8 - i√7/8 = 1/8 (-3 - i√7)