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IngridaSobral
@IngridaSobral
October 2019
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Escreva na reduzida as equações de 2º grau
(Y-2)²=4-Y(Y+3)
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AndrLucas
Vamos resolve o (y-2)² primeiro:
(y-2)·(y-2) = y² - 2y - 2y + 4
y² - 4y + 4
y² - 4y + 4 = 4 - y² - 3y
y² - 4y + 4 = - y² - 3y + 4
Agora vamos passar
2y² - y = 0
y · (y-1) = 0
y = 0 e y = 1
1 votes
Thanks 1
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(y-2)·(y-2) = y² - 2y - 2y + 4
y² - 4y + 4
y² - 4y + 4 = 4 - y² - 3y
y² - 4y + 4 = - y² - 3y + 4
Agora vamos passar
2y² - y = 0
y · (y-1) = 0
y = 0 e y = 1