Esta formula mostra a relação entre as duas escalas;celsiues (tc)e fahrenheir (tf)
\frac{tc}{y]5} = \frac{tf}{9} -32
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Esta formula mostra a relação entre as duas escalas;celsiues (tc)e fahrenheir (tf)
\frac{tc}{y]5} = \frac{tf}{9} -32
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Verified answer
F=(9/5)(C+32)F=(9/5)(0+32)
F=(9/5)(32)
F=(32:5) x 9
F=57,6 ºF
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