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Johannwieth
@Johannwieth
October 2019
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Exponencial: 5^x+125×5^-x=30
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guifilipe2
5^x + 125 . 5 ^-x = 30
5^x + 125 . (5 ^x)^-1 = 30
considere que 5^x = y
y + 125 y^-1 = 30
y + 125/y = 30
(y^2 + 125 )/y = 30
y^2 - 30y + 125 = 0
pela fórmula de bhaskara , temos :
y = (30 (+ou -) 20 ) / 2
y= 5 ou y = 25
assim , 5^x = 5 ^1 ou 5^x = 25
x = 1 5^x = 5^2
x = 2
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Lista de comentários
5^x + 125 . (5 ^x)^-1 = 30
considere que 5^x = y
y + 125 y^-1 = 30
y + 125/y = 30
(y^2 + 125 )/y = 30
y^2 - 30y + 125 = 0
pela fórmula de bhaskara , temos :
y = (30 (+ou -) 20 ) / 2
y= 5 ou y = 25
assim , 5^x = 5 ^1 ou 5^x = 25
x = 1 5^x = 5^2
x = 2