A) 60°
πRad------180°
x----------60°
180x=60
x=60/180 → 30/90 → 15/45 → 5/15 = 1/3πRad
_______________________________________________________
Utilizaremos o mesmo método da alternativa (a), ou seja, todos serão divididos por 180°.
B) 15°
15/180 → 5/60 = 1/12πRad
C) 75°
75/180 → 25/60 → 5/12πRad
D) 225°
225/180 → 75/60 → 25/20 = 5/4πRad
E) 240°
240/180 → 120/90 → 60/45 → 20/15 = 4/3πRad
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Lista de comentários
60
----- π
180
π
---
3
b) 15°
15
---- π
180
π
---
12
c) 75°
75
---- π
180
5π
----
12
d) 225°
225
------- π
180
5π
-----
4
e) 240°
240
------- π
180
4π
-----
3
Boa tarde!
A) 60°
πRad------180°
x----------60°
180x=60
x=60/180 → 30/90 → 15/45 → 5/15 = 1/3πRad
_______________________________________________________
Utilizaremos o mesmo método da alternativa (a), ou seja, todos serão divididos por 180°.
_______________________________________________________
B) 15°
15/180 → 5/60 = 1/12πRad
_______________________________________________________
C) 75°
75/180 → 25/60 → 5/12πRad
_______________________________________________________
D) 225°
225/180 → 75/60 → 25/20 = 5/4πRad
_______________________________________________________
E) 240°
240/180 → 120/90 → 60/45 → 20/15 = 4/3πRad
_______________________________________________________
Att;Guilherme Lima