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senseikarina
@senseikarina
July 2023
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FAVOR RESPONDER SOMENTE SE TIVER CERTEZA.
A RESPOSTA ERRADA JÁ TENHO E PRECISO MUITO DOS PONTOS, E CONSEQUENTEMENTE DA RESPOSTA CORRETA.
MUITÍSSIMO OBRIGADA.
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[tex]\displaystyle \sf f'(x) = cos(x)+3x^2 \\\\ \frac{dy }{dx} =cos(x)+3x^2 \\\\\\ dy = cos(x)dx +3x^2dx \\\\ \int dy = \int cos(x)dx +\int 3x^2dx \\\\\\\ y = sen(x)+\frac{3x^{2+1}}{2+1} + C \\\\\\ y = sen(x)+x^3+C \\\\\ \Large\boxed{\sf \ f(x) = sen(x)+x^{3}+C \ }\checkmark[/tex]
opção 3
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[tex]\displaystyle \sf f'(x) = cos(x)+3x^2 \\\\ \frac{dy }{dx} =cos(x)+3x^2 \\\\\\ dy = cos(x)dx +3x^2dx \\\\ \int dy = \int cos(x)dx +\int 3x^2dx \\\\\\\ y = sen(x)+\frac{3x^{2+1}}{2+1} + C \\\\\\ y = sen(x)+x^3+C \\\\\ \Large\boxed{\sf \ f(x) = sen(x)+x^{3}+C \ }\checkmark[/tex]
opção 3