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NielGamer022
@NielGamer022
December 2019
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Função Quadráticas
Calcule o zero da função f(x)=x elevado a 2 -6x + 5
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Flait2
Delta= b^2 - 4*A*C
Delta= 6^2 -4*1*5
Delta= 36-20
Delta= 16
Delta= √16= 4
X1= (-(-6)+4)/2 = 10/2= 5
X2 = (-(-6)-4)/2=2/2=1
0 votes
Thanks 1
nancitieco
F(x) = x² - 6x + 5
x² - 6x + 5 = 0
a = 1 ; b = -6 ; c = 5
Δ = b² - 4 . a .c
Δ = (-6)² - 4 . 1 . 5
Δ = 36 - 20
Δ = 16
x = (- b + - √Δ )/ 2.a
x = (6 + √ 16 ) / 2. 1
x' = ( 6 + 4 ) / 2
x' = 10 / 2
x' = 5
x'' = (6 - 4) / 2
x'' = 2 / 2
x'' = 1
1 votes
Thanks 1
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Delta= 6^2 -4*1*5
Delta= 36-20
Delta= 16
Delta= √16= 4
X1= (-(-6)+4)/2 = 10/2= 5
X2 = (-(-6)-4)/2=2/2=1
x² - 6x + 5 = 0
a = 1 ; b = -6 ; c = 5
Δ = b² - 4 . a .c
Δ = (-6)² - 4 . 1 . 5
Δ = 36 - 20
Δ = 16
x = (- b + - √Δ )/ 2.a
x = (6 + √ 16 ) / 2. 1
x' = ( 6 + 4 ) / 2
x' = 10 / 2
x' = 5
x'' = (6 - 4) / 2
x'' = 2 / 2
x'' = 1