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May 2020
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Calcule a quantidade de calor necessário para transformar 50g de água, a 100°C, e vapor de água, 140°C.
Dados: Calor latente de vaporização= 540cal/g ; Calor especifico do vapor = 0,5cal/g °C
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uesleihenrique
Temos :
Q =m.c.Δ ---------> Q= 50.0,5.39ºc---->>Q=975 cal
Q2 = m.L ------> Q = 50.540 = 27000 cal
Q+Q2 = 27975 Cal ou
1 cal = 4 Joules
11,19 KJ
1 votes
Thanks 4
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Q =m.c.Δ ---------> Q= 50.0,5.39ºc---->>Q=975 cal
Q2 = m.L ------> Q = 50.540 = 27000 cal
Q+Q2 = 27975 Cal ou
1 cal = 4 Joules
11,19 KJ