GENTE EU PRECISO DE AJUDA JA PERGUNTEI TRES VEZES ISSO E NINGUEM ME AJUDA E PARA AMANHÃ.... Pergunta de ideia deCarolyne1234

lavinnea $a) \\ \frac{3}{4} . \sqrt{ \frac{25}{36} } -( \frac{6}{5} \div \frac{12}{5} + \frac{1}{4} )^3= \\ \\ \frac{3}{4} \times \frac{5}{6} -( \frac{6}{5} \times \frac{5}{12} + \frac{1}{4} )^3= \\ \\ \frac{\not3}{4} \times \frac{5}{\not6_2} -( \frac{\not6}{\not5} \times \frac{\not5}{\not12_2} + \frac{1}{4} )^3= \\ \\ \frac{5}{8} -( \frac{1}{2} + \frac{1}{4})^3 = \\ \\ \frac{5}{8} -( \frac{2+1}{4} )^3= \\ \\ \frac{5}{8} -( \frac{3}{4} )^3= \frac{5}{8} - \frac{27}{64}= \frac{40-27}{64} = \frac{13}{64}$

-------------------------------------------

b)

$\frac{7}{3} + \sqrt{ \frac{49}{64} } \div \frac{21}{8} - (\frac{3}{8} \times \frac{16}{9} )^2= \\ \\ \frac{7}{3} + \frac{7}{8} \times \frac{8}{21} -( \frac{\not3}{\not8} \times\frac{\not16^2}{\not9_3} )^2= \\ \\ \frac{7}{3} + \frac{\not7}{\not8} \times \frac{\not8}{\not21_3} -( \frac{2}{3} )^2= \\ \\ \frac{7}{3} + \frac{1}{3} -( \frac{4}{9} )= \\ \\ \frac{7}{3} + \frac{1}{3} - \frac{4}{9} = \\ \\mmc(3,9)=9 \\ \\ \frac{21+3-4}{9} = \frac{24-4}{9} = \frac{20}{9}$

Carolyne1234 Obrigado :-} :-}

Natov de nada

Lista de comentários

Recomendar perguntas

Helpful Links

Helpful Social