Help!! Urgente!!!Calcular, mostrando desenvolvimento... Obrigado! ^

April 2020 1 56 Report

Help!! Urgente!!!

Calcular, mostrando desenvolvimento...

Obrigado! ^_^

Lista de comentários

Verified answer

A) Ricardo
(11/2 - 11/4) . (2/5 + 1/25) mmc de 2 e 4= 4 mmc de 5 e 25 =25
(22 -11)/4 . ( 10 + 1)/25
(11/4) . (11/25)
121/ 100

b) Luciana
1+ 1/2 .5/4 -2.(5/2-2/5)
1+5/8 -10/6 +4/15 mmc de 1,8,6 e 15 = 120
(120 +75 -200 +32)/120
(120 +75 +32 -200)/120
(227 -200)/120
27/120 simplificando 27 e 120 por 3
9/40

c) Gabriela
3/2 + ( 1+ 1/2) . (2 + 1 1/3) . (3 + 1/4)
3/2 + ( 1+1/2) . ( 2+ 4/3) . (3+1/4) mmc de 1 e 2 =2 ; 1 e 3=3 ; 1 e 4 =4
3/2 + (2+1)/2 . (6+4)/3 . ( 12+1)/4
3/2 + (3/2). (10/3) . (13/4) resolvendo a multiplicação
3/2 + 390/24 mmc de 2 e 24 = 24
(36 + 390)/24
426/24 simplificando 426 e 24 por 6
71/4

d) Priscila
18/35.( 2/5 +21/15 . 5/49) . (7/2 -1)
18/35 .( 2/5 + 105/735) .( 7/2 - 1) mmc de 5 e 735=735 ; 2 e 1=2
18/35.(294 +105)/735 . (7/2 -2)
18/35. (399/735) . (5/2) simplificando 399 e 735 por 7
18/35.(57/105) . (5/2)
5130/7350 dividido por 1000
513/735

e) Maurício
2/5.[1+2/3.(1/4 - 1/5)]
2/5.[1+ 2/12 -2/15] mmc de 1,12 e 15 = 60
2/5.[60 +10 -8]/60
2/5.[ 70-8]/60
2/5. 62/60
124/300 simplificando 124 e 300 por 4
31/75

3 votes Thanks 3

LuTodeschini Obrigado