Inserir oito meios aritméticos entre 40 e -5.... Pergunta de ideia deJoaovitorassisp9huv2

Joaovitorassisp9huv2 @Joaovitorassisp9huv2

August 2019 2 28 Report

Inserir oito meios aritméticos entre 40 e -5

eduarda1000 N = 10
a1 = 40
an = -5
r = ?

-5 = 40 + (10-1) . r
-5=40+9r
-45=9r
r=-5

40, 35, 30, 25, 20, 15, 10, 5, 0, -5

0 votes Thanks 1

helviotedesco Razão da PA:

an = a1 + ( n -1) . r
-5 = 40 + ( 10 -1) . r
-5 = 40 + 9r
-45 = 9r
r = -5

===

an = a1 + ( n -1) . r = an
an = 40 + ( 1 -1) .-5 = 40
an = 40 + ( 2 -1) .-5 = 35
an = 40 + ( 3 -1) .-5 = 30
an = 40 + ( 4 -1) .-5 = 25
an = 40 + ( 5 -1) .-5 = 20
an = 40 + ( 6 -1) .-5 = 15
an = 40 + ( 7 -1) .-5 = 10
an = 40 + ( 8 -1) .-5 = 5
an = 40 + ( 9 -1) .-5 = 0
an = 40 + ( 10 -1) .-5 = -5

PA = ( 40, 35, 30, 25, 20, 15, 10, 5, 0 ,-5 )

0 votes Thanks 1

helviotedesco De nada.