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Samukael2003
@Samukael2003
June 2019
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Insira os 4 meios geométricos entre 2 e 486, nesta ordem
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rbgrijo2011
Q^(n-1) = an/a1
q^(6-1) = 486/2
q^5 = 243
(q)^5 = (3)^5
q = 3
PG: (2, 6, 18, 54, 162, 486)
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q^(6-1) = 486/2
q^5 = 243
(q)^5 = (3)^5
q = 3
PG: (2, 6, 18, 54, 162, 486)