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Rafaelacaires4588
@Rafaelacaires4588
October 2019
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Insira quatro meios aritméticos entre 7 e 17.
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Osvaldodossantos4
A1,a2,a3,a4,a5,a6
a6=a1+5r
17=7+5r
r=2
a2=a1+r =7+2=9
a3=a1+2r=7+2x2=11
a4=a1+3r=7+3x2=13
a5=a1+4r=7+4x2=15
PA(7,9,11,13,15,17)
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a6=a1+5r
17=7+5r
r=2
a2=a1+r =7+2=9
a3=a1+2r=7+2x2=11
a4=a1+3r=7+3x2=13
a5=a1+4r=7+4x2=15
PA(7,9,11,13,15,17)