[tex] > resolucao \\ \\ progressao \: \: aritmetica \\ \\ an = a1 + (n - 1)r \\ 45 = 15 + (11 - 1)r \\ 45 = 15 + 10r \\ 45 - 15 = 10r \\ 30 = 10r \\ r = \frac{30}{10} \\ r = 3 \\ \\ \\ \geqslant \: o \: 6 \: termo \: da \: pa \\ \\ a6 = a1 + 5r \\ a6 = 15 + 5 \times 3 \\ a6 = 15 + 15 \\ a6 = 30 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant [/tex]
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[tex] > resolucao \\ \\ progressao \: \: aritmetica \\ \\ an = a1 + (n - 1)r \\ 45 = 15 + (11 - 1)r \\ 45 = 15 + 10r \\ 45 - 15 = 10r \\ 30 = 10r \\ r = \frac{30}{10} \\ r = 3 \\ \\ \\ \geqslant \: o \: 6 \: termo \: da \: pa \\ \\ a6 = a1 + 5r \\ a6 = 15 + 5 \times 3 \\ a6 = 15 + 15 \\ a6 = 30 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant [/tex]