O equilíbrio H2 (g) + Cl2 (g) <--> 2HCl (g) se estabelece com:
{H2} = 2mol/L
{Cl2} = 0,5 mol/L
{HCl} = 2 mol/ L
Calcule o Kc
{H2} = 2mol/L
{Cl2} = 0,5 mol/L
{HCl} = 2 mol/ L
Calcule o Kc
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Verified answer
H2 (g) + Cl2 (g) ⇆ 2 HClKc = [HCl]² / [H2][Cl2]
Kc = 2² / 2 . 0,5
Kc = 4 / 1
Kc = 4