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LUCAS956956
@LUCAS956956
October 2019
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Quantos gramas de NaCl (sal de cozinha) são necessários para preparar 3,0 L de uma solução cuja concentração é de 25 g/L?
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3 litros ------ x
1 litro -------- 25
1x = 25 . 3
1x = 75
x = 75 gramas
1 votes
Thanks 1
Louis2070
Volume = 3,0 L
C = 25 g/L
Massa = ? (vamos descobrir)
C = m / V
25 = m / 3,0
m = 25
.
3,0
m =
75 g
3 votes
Thanks 2
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3 litros ------ x
1 litro -------- 25
1x = 25 . 3
1x = 75
x = 75 gramas
C = 25 g/L
Massa = ? (vamos descobrir)
C = m / V
25 = m / 3,0
m = 25 . 3,0
m = 75 g