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GabiNanda
@GabiNanda
January 2020
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Log (x+6) + log (x+5) =3 log5
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superaks
Condição de existência dos logaritmos é:
x+6 > 0
x > - 6
x+5 > 0
x > -5
S = (x ∈ |R | x > - 5 )
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x+6 > 0
x > - 6
x+5 > 0
x > -5
S = (x ∈ |R | x > - 5 )