Log3 (2x +1) + log3 (x + 8) = 3.... Pergunta de ideia deMylenasilva28

Mylenasilva28 @Mylenasilva28

May 2020 1 49 Report

Log3 (2x +1) + log3 (x + 8) = 3

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nandofilho10 $log3 ^(^2^x^+^1)^+ log3 ^(^x^+^8) = 3$

$log3 ^ \frac{(^2^x^+^1)}{ (^x^+^8) } = 3$

$\frac{(^2^x^+^1)}{ (^x^+^8) } =3^ 3$

$\frac{(^2^x^+^1)}{ (^x^+^8) } =27$

$(2x + 1) = 27x + 216$

$- 25x = 215$

$x =- \frac{ 215}{25}$

$x = - ( \frac{43}{5} )$

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