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MISAKEMEI30
@MISAKEMEI30
June 2019
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Me ajudeeeeeeem pfv
x^2+10x+25=144
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helitonsilva590
Vamos lá
X² + 10X + 25 = 144
X² + 10X + 25 - 144 = 0
X² + 10X - 119 = 0
Os coeficientes
A = 1 ; B = 10 ; C = - 119
Delta :
Δ = b² - 4 • a • c
Δ = 10² - 4 • 1 • ( - 119 )
Δ = 100 + 476
Δ = 576
Calculando as raízes
X = - b ± √ Δ / 2 • a
X = - 10 ± √ 576 / 2 • 1
X = - 10 ± 24 / 2
X1 = - 10 + 24 / 2 = 14 / 2 = 7
X2 = - 10 - 24 / 2 = - 34 / 2 = - 17
RESPOSTA :
S ( 7 , - 17 )
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Lista de comentários
X² + 10X + 25 = 144
X² + 10X + 25 - 144 = 0
X² + 10X - 119 = 0
Os coeficientes
A = 1 ; B = 10 ; C = - 119
Delta :
Δ = b² - 4 • a • c
Δ = 10² - 4 • 1 • ( - 119 )
Δ = 100 + 476
Δ = 576
Calculando as raízes
X = - b ± √ Δ / 2 • a
X = - 10 ± √ 576 / 2 • 1
X = - 10 ± 24 / 2
X1 = - 10 + 24 / 2 = 14 / 2 = 7
X2 = - 10 - 24 / 2 = - 34 / 2 = - 17
RESPOSTA :
S ( 7 , - 17 )