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Leticialaramoreira
@Leticialaramoreira
January 2020
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Me ajudem, dou 30 pontos!
Seja a função f: R ➡ R dada por f(x)=4x-1. Calcule
a) f(-2) + f(2)=
b) f(3) . f(4)=
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Rodrigo3200
Dado:
f(x) = 4x - 1
a) f(-2) + f(2),=
Substitua os valores entre parenteses no lugar do x
seja
x = - 2
, temos:
f(
- 2
) = 4.(
-2
) - 1
f(
- 2
) = - 8 - 1
f(- 2) = - 9
seja
x = 2
f(
2
) = 4.
2
- 1
f(
2
) = 8 - 1
f(2) = 7
Portanto:
f(- 2) + f(2) = - 9 + 7 = - 2
b) f(3).f(4)
seja
x = 3
f(
3
) = 4.
3
- 1
f(
3
) = 12 - 1
f(
3
) = 11
seja
x = 4
f(
4
) = 4.
4
- 1
f(
4
) = 16 - 1
f(
4
) = 15
Portanto:
f(3).f(4) = 11.15 = 165
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Lista de comentários
f(x) = 4x - 1
a) f(-2) + f(2),=
Substitua os valores entre parenteses no lugar do x
seja x = - 2, temos:
f(- 2) = 4.(-2) - 1
f(- 2) = - 8 - 1
f(- 2) = - 9
seja x = 2
f(2) = 4.2 - 1
f(2) = 8 - 1
f(2) = 7
Portanto: f(- 2) + f(2) = - 9 + 7 = - 2
b) f(3).f(4)
seja x = 3
f(3) = 4.3 - 1
f(3) = 12 - 1
f(3) = 11
seja x = 4
f(4) = 4.4 - 1
f(4) = 16 - 1
f(4) = 15
Portanto: f(3).f(4) = 11.15 = 165