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Mayara40405
@Mayara40405
January 2020
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ME AJUDEM POR FAVOR
1-Considerando:
√2=1,414,√3=1,732 e √5 2,236, Determine o valor númerico das expressões
a)2√2+3√3+6√5=
b)10√5+6√2+8√3=
c)2√2+√3+√5=
d)-4(√2+√3+√5)=
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LeoOliveira1304
A) 2x1,414 + 3x1,732 + 6x 2,236 =
2,828 + 5,196 + 13,416=
21,44
b) 10x 2,236 + 6x1,414 + 8x1,732
22,36 + 8,484 + 13,856 = 44,7
c) 2x 1,414 + 1,732 + 2,236 = 6,796
d) -4x1,414 - 4x1,732 - 4x2,236 = -5,656 - 6,928 - 8,944 = -21,528
5 votes
Thanks 9
Mayara40405
Mt obgd
LeoOliveira1304
desculpa, eh q eu tinha apertado responder sem querer
LeoOliveira1304
ja respondi o resto
Mayara40405
Assim mt obgd
Mayara40405
Vc respondeu q c e a d?
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Lista de comentários
2,828 + 5,196 + 13,416=
21,44
b) 10x 2,236 + 6x1,414 + 8x1,732
22,36 + 8,484 + 13,856 = 44,7
c) 2x 1,414 + 1,732 + 2,236 = 6,796
d) -4x1,414 - 4x1,732 - 4x2,236 = -5,656 - 6,928 - 8,944 = -21,528