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Guguu113
@Guguu113
December 2019
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ME AJUDEM POR FAVOR , É PARA AGORA !!!
COMO RESOLVER ESSA EQUAÇÃO
5x²-13x+6???
55 PONTOS , ME AJUDEM POR FAVOR !!!
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Verified answer
Fórmulas:
Δ= b²-4.a.c
x= -b+₋√Δ/2.a
5x²-13x+6=0
a= 5, b= -13, c=6
Δ= (-13)-4.5.6
Δ= 169-120
Δ= 49
x= 13+₋√49/10
x'= 13+7/10= 2
x''= 13-7/10= 6/10⇒3/5
Resposta: 2 e
3 votes
Thanks 2
pedrophml
Verified answer
5x²-13x+6=0
Delta =b²-4ac
Delta =(-13)²-4×5×6
Delta =169-120
Delta=49
Raiz de delta =7
Usando a formula de bhaskara
X=13±7/10
X1=20/10=2
X2=6/10=3/5
1 votes
Thanks 1
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Lista de comentários
Verified answer
Fórmulas:Δ= b²-4.a.c
x= -b+₋√Δ/2.a
5x²-13x+6=0
a= 5, b= -13, c=6
Δ= (-13)-4.5.6
Δ= 169-120
Δ= 49
x= 13+₋√49/10
x'= 13+7/10= 2
x''= 13-7/10= 6/10⇒3/5
Resposta: 2 e
Verified answer
5x²-13x+6=0Delta =b²-4ac
Delta =(-13)²-4×5×6
Delta =169-120
Delta=49
Raiz de delta =7
Usando a formula de bhaskara
X=13±7/10
X1=20/10=2
X2=6/10=3/5