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Joaozao
@Joaozao
April 2020
1
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Me ajudem por favor nessa questão
efetue as potenciações indicadas:
d (
- 2
ab²)³ =
5
e(10pq³)² =
f)(-0,3x²y³)² =
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3478elc
Verified answer
D (
- 2
ab²)³ = - 8 a^3b^6
5 125
e(10pq³)² = 100p^2q^6
f)(-0,3x²y³)² = 0,09x^4Y^6
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Verified answer
D (- 2 ab²)³ = - 8 a^3b^65 125
e(10pq³)² = 100p^2q^6
f)(-0,3x²y³)² = 0,09x^4Y^6