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ReneOtto
@ReneOtto
July 2022
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Um corpo oscila horizontalmente, preso a uma mola, com amplitude de 5 cm e energia total de 10 J. Qual a constante elástica da mola?
Escolha uma:
8000 N/m;
400 N/m;
800 N/m;
80 N/m.
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priestxdd
10=k.x²/2
k=10/(5.10
⁻²)²/2
K=10/25.10⁻⁴/2
K=20/25.10⁻⁴
K=8000 N/M
1 votes
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k=10/(5.10⁻²)²/2
K=10/25.10⁻⁴/2
K=20/25.10⁻⁴
K=8000 N/M