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Arrythersus
@Arrythersus
December 2019
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Na expressão PR + PS + QR + QS= X qual o valor de X sabendo que P + Q=222 e R + S=55?
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brunolima2017
Podemos resolver colocado em evidecia os termos iguais deste modo;
PR + PS + QR + QS = X
P(R+S) + Q(R+S) = X , mas R+S=55
P(55) + Q(55) = X
55P + 55Q = X
55(P+Q) = X , mas P+Q=222
55(222) = X
X = 12210
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Olá, tudo bem?
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PR + PS + QR + QS = X
P(R+S) + Q(R+S) = X , mas R+S=55
P(55) + Q(55) = X
55P + 55Q = X
55(P+Q) = X , mas P+Q=222
55(222) = X
X = 12210