Bonjour,
f(1) = -1² + 4 = -1 + 4 = 3 d'où A(1 ; 3)
g(1) = 1² - 4 + 6 = 1 - 4 + 6 = 3 d'où A(1 ; 3)
f'(1) = - 2 × 1 = -2
g'(1) = 2 × 1 + (-4) × 1 = 2 - 4 = -2
f(1) = g(1) et f'(1) = g'(1) donc tangente commune au point A
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Bonjour,
f(1) = -1² + 4 = -1 + 4 = 3 d'où A(1 ; 3)
g(1) = 1² - 4 + 6 = 1 - 4 + 6 = 3 d'où A(1 ; 3)
f'(1) = - 2 × 1 = -2
g'(1) = 2 × 1 + (-4) × 1 = 2 - 4 = -2
f(1) = g(1) et f'(1) = g'(1) donc tangente commune au point A