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Weinny
@Weinny
December 2019
1
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Números complexos
efetue: (1+i).(2-i).(3+2i)
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laurapaes12
(1 + i)(2 - i) = 2 -i + 2i -i² = 2 + i + 1
(3 + 2i)( 2 + i + 1) = 6 + 3i + 3 - 4i + 2i² + 2i = 9 + i - 2 = 7 + i
Resultado : 7+9i
7 votes
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Lista de comentários
(3 + 2i)( 2 + i + 1) = 6 + 3i + 3 - 4i + 2i² + 2i = 9 + i - 2 = 7 + i
Resultado : 7+9i