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Giliv17
@Giliv17
January 2020
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O 5º termo no desenvolvimento do binômio (x-1) elevado a 7
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Ninuma
5* Termo do binômio (x - 1) ^ 7
( n | k ) * x^(n-k) * (-1)^k
k = 5 - 1 = 4
n =7
(7 | 4) * x^(7-4) * (-1)^4 =
(7 * 6 * 5 * 4! * x^3 * 1) / 4! * (7 - 4)! =
(7 * 6 * 5 * x^3) / 3! =
7 * 5 * x^3 =
35 x^3
5 votes
Thanks 2
Giliv17
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Ninuma
de nada, não custa nada ajudar
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( n | k ) * x^(n-k) * (-1)^k
k = 5 - 1 = 4
n =7
(7 | 4) * x^(7-4) * (-1)^4 =
(7 * 6 * 5 * 4! * x^3 * 1) / 4! * (7 - 4)! =
(7 * 6 * 5 * x^3) / 3! =
7 * 5 * x^3 =
35 x^3