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Thomas138
@Thomas138
December 2019
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O instante que a bola se encontra a 75 m do solo ?h(t)=40t-5t elevado a 2
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A=-5
b=40 c=-75
-5t+40t=75
-5t+40t-75=0 t1=-40+10/-10=-30/-10=3
Δ=40²-4.(-5).(-75) t2=-40-10/-10=-50-10/-10=-60/-10=6
Δ=1600-1500
Δ=100
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b=40 c=-75
-5t+40t=75
-5t+40t-75=0 t1=-40+10/-10=-30/-10=3
Δ=40²-4.(-5).(-75) t2=-40-10/-10=-50-10/-10=-60/-10=6
Δ=1600-1500
Δ=100