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Leanashe
@Leanashe
December 2019
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O limite de x tendendo a 0 (raiz de x²+x+1)-1 dividido por x
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albertrieben
Boa dia.
lim (√(x² + x + 1)-1)/x
d/dx(√(x² + x + 1) - 1) = (2x + 1)/(2√(x² + x + 1))
d/dx (x) = 1
lim (√(x² + x + 1)-1)/x = (2x + 1)/(2√(x² + x + 1)) = 1/2
x-->0 x-->0
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Leanashe
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lim (√(x² + x + 1)-1)/x
d/dx(√(x² + x + 1) - 1) = (2x + 1)/(2√(x² + x + 1))
d/dx (x) = 1
lim (√(x² + x + 1)-1)/x = (2x + 1)/(2√(x² + x + 1)) = 1/2
x-->0 x-->0