Articles
Register
Sign In
Search
Kiritoyo
@Kiritoyo
December 2019
1
42
Report
O valor da Integral é:
Escolha uma:
a. 2
b. 5
c. 1
d. -5
e. 0
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
saezo
3 1 1 1
∫ ∫ ∫ y dv ∫∫∫ y dy dz dx =∫∫y^2/2] dz dx
1 1 -1 -1 1
∫∫1^2/2-(-1^2/2dz dx=∫∫odz dx=∫∫ z dx=∫z^2/2] dx
3 o
∫1^2/2 dx=∫1/2 dx=1/2 ∫x^2/2=1/2[x^2/2]
1
1/2[3^2/2]-[ 1^2/2 ] = 1/2[9/2 -1/2 ]
1/2[8/2] = 8/4 = 2
10 votes
Thanks 24
More Questions From This User
See All
Kiritoyo
December 2019 | 0 Respostas
Responda
Recomendar perguntas
Deividyfreitas
May 2020 | 0 Respostas
BlackShot
May 2020 | 0 Respostas
Vanessakellen
May 2020 | 0 Respostas
Guiduarter
May 2020 | 0 Respostas
Mrzaine
May 2020 | 0 Respostas
O QUE SERIA AUTONOMIA?
Grazifer
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
a palavra rapidez formou se de qual derivacao
Celiana
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
Anatercia
May 2020 | 0 Respostas
×
Report "O valor da Integral é: Escolha uma: a. 2 b. 5 c. 1 d. -5 e. 0.... Pergunta de ideia de Kiritoyo"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
∫ ∫ ∫ y dv ∫∫∫ y dy dz dx =∫∫y^2/2] dz dx
1 1 -1 -1 1
∫∫1^2/2-(-1^2/2dz dx=∫∫odz dx=∫∫ z dx=∫z^2/2] dx
3 o
∫1^2/2 dx=∫1/2 dx=1/2 ∫x^2/2=1/2[x^2/2]
1
1/2[3^2/2]-[ 1^2/2 ] = 1/2[9/2 -1/2 ]
1/2[8/2] = 8/4 = 2