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090103W
@090103W
November 2019
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Os segmentos AB, CD, EF e GH são proporcionais. sabendo que AB= X+2, CD=2X-2, EF=20cm e GH=32 qual o valor de X?
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Osvaldo65
De acordo com os dados do problema podemos estabelecer a seguinte proporção:
(x+2)/(2x-2) = 20/32
32(x+2)=20(2x-2)
32x+64=40x-40
32x-40x=-40-64
-8x=-104
x=-104/-8 =13
Resposta: x = 13
1 votes
Thanks 1
luccasreis13
Proporcional =
Divisão ou sobre algo
AB
=
EF
=>
X + 2
=
20
=>
20.(2.X-2) = 32.(X + 2)
CD GH
2X - 2 32 40.X - 40 = 32.X + 64
40.X - 32.X = 64 + 40
8.X = 104
X = 13
0 votes
Thanks 1
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(x+2)/(2x-2) = 20/32
32(x+2)=20(2x-2)
32x+64=40x-40
32x-40x=-40-64
-8x=-104
x=-104/-8 =13
Resposta: x = 13
AB = EF => X + 2 = 20 => 20.(2.X-2) = 32.(X + 2)
CD GH 2X - 2 32 40.X - 40 = 32.X + 64
40.X - 32.X = 64 + 40
8.X = 104
X = 13