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RodriguesFernanda
@RodriguesFernanda
January 2020
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(PAES)Os valores de x que satisfazem a equação log(x^2-15)=2 são
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Conceitualmente
x^2 - 15x = 10^2
x^2 - 15x - 100 = 0
Fatorando
(x - 20)(x + 5) = 0
x - 20 = 0
x1 = 20
x + 5 = 0
x2 = - 5
S = {- 5, 20}
OS VALORES SÃO - 5 E 20
0 votes
Thanks 1
Nooel
Usando a propriedade de log que será
Logₐ B= X ⇒ B=aˣ
Log(x²-15x)=2
x²-15x=10²
x²-15x-100=0
Bhaskara
Δ=-15²-4.1.(-100)
Δ=225+400
Δ=625
X=15+-√625/2
X'=15+25/2 = 40/2 = 20
X''=15-25/2 = -10/2 = -5
S= (20 , -5)
Letra D
1 votes
Thanks 1
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Lista de comentários
Verified answer
Conceitualmente
x^2 - 15x = 10^2
x^2 - 15x - 100 = 0
Fatorando
(x - 20)(x + 5) = 0
x - 20 = 0
x1 = 20
x + 5 = 0
x2 = - 5
S = {- 5, 20}
OS VALORES SÃO - 5 E 20
Logₐ B= X ⇒ B=aˣ
Log(x²-15x)=2
x²-15x=10²
x²-15x-100=0
Bhaskara
Δ=-15²-4.1.(-100)
Δ=225+400
Δ=625
X=15+-√625/2
X'=15+25/2 = 40/2 = 20
X''=15-25/2 = -10/2 = -5
S= (20 , -5)
Letra D